Question

一道解不等式的数学题解不等式：|x²-2|x|-2|≥1

Answer 1

|x²-2|x|-2|≥1

||x|²-2|x|-2|≥1

|(|x|-1)²-3|≥1

(|x|-1)²-3≥1或 (|x|-1)²-3≤-1

(|x|-1)²≥4或 (|x|-1)²≤2

|x|-1≥2或|x|-1≤-2或|x|-1≤√2或|x|-1≤-√2

|x|≥3或|x|≤√2+1

x≥3或x≤-3或-√2-1≤或x≤√2+1