Question

因式分解ax^2+bx^2-a^2x-b^2x-2abx+a^2b+ab^2

Answer 1

原式=(a+b)x^2-(a^2+b^2+2ab)x+ab(a+b)

=(a+b)x^2-(a+b)^2x+ab(a+b)

=(a+b)[x^2-(a+b)x+ab]

=(a+b)(x-a)(x-b)