① nO = 0.25mol × 4 = 1 mol
② n Al(OH)3 = 3.01 × 10 ^ 23 /(6.02 × 10 ^ 23)mol
= 0.5 mol
n O = 0.5 mol × 3 = 1.5 mol
③ n O2 = 8 g /(16 g / mol)= 0.5 mol
n O = 0.5 mol × 2 = 1 mol
④ n O3 = 11.2L / (22.4 L / mol)= 0.5 mol
n O = 0.5 mol × 3 = 1.5 mol
① nO = 0.25mol × 4 = 1 mol
② n Al(OH)3 = 3.01 × 10 ^ 23 /(6.02 × 10 ^ 23)mol
= 0.5 mol
n O = 0.5 mol × 3 = 1.5 mol
③ n O2 = 8 g /(16 g / mol)= 0.5 mol
n O = 0.5 mol × 2 = 1 mol
④ n O3 = 11.2L / (22.4 L / mol)= 0.5 mol
n O = 0.5 mol × 3 = 1.5 mol