还需要查表查到
△fHmθ(H2O,l)
△fHmθ(HCl,g)
的值.
题目已知：
Ag2O(s) + 2HCl (g) = 2AgCl(s) + H2O(l) △rHmθ = - 324.9 kJ/mol
△rHmθ = △fHmθ (H2O,l) + 2△fHmθ (AgCl,s)
- △fHmθ (Ag2O,s)- 2△fHmθ(HCl,g)
= - 324.9
求△fHmθ(AgCl,s)
上式中已知：
△fHmθ (Ag2O,s) = - 31.0 kJ/mol
所以还需要查表查出相关数据才能计算：
△fHmθ(H2O,l)
△fHmθ(HCl,g)