计算题:1.根号12-根号1/2-(根号1/8-根号27) 2.(7倍根号54-3倍根号21+4根号15)÷根号3

1个回答

  • 根号12-根号1/2-(根号1/8-根号27)

    =2√3-√2/2-(√2)/4+3√3

    =5√3-(3√2)/4

    (7倍根号54-3倍根号21+4根号15)÷根号3

    =(21√6-3√21+4√15)÷√3

    =21√2-3√7+4√5

    (2倍根号3-1)平方+(根号3-2)(根号3+6)

    =12-4√3+1+3+6√3-2√3-12

    =4

    1-2倍根号3/2+根号3-(2/根号2-1)平方+12/根号3

    =1/2-√3+√3-(2√2+1)²+4√3

    =1/2-(8+4√2+1)+4√3

    =1/2-9-4√2+4√3

    =-17/2-4√2+4√3

    5.(a倍根号8a)-(2a平方倍根号1/8a)+(3倍根号2a立方)

    =2a√2a-1/2a√2a+3a√2a

    =9/2a√2a