1、解分式方程:X减2分之X 减1等于4减X²分之2

1个回答

  • 1、解分式方程:X减2分之X 减1等于4减X²分之2

    x/(x-2) -1=2/(4-x²)

    x/(x-2) -1=-2/(x²-4)

    x(x+2) -(x²-4)=-2

    x²+2x -x²+4=-2

    2x=-6

    x=-3

    经检验x=-3是方程的解

    2

    X²减1分之X²减2X÷(X减1减X加1分之2X减1)其中X等于2

    =(x²-2x)/(x²-1) ÷(x-1 - (2x-1)/(x+1))

    =x(x-2)/(x²-1) ÷ ((x-1)(x+1)-(2x-1))/(x+1)

    =x(x-2)/(x²-1) ÷ (x^2-1-2x+1)/(x+1)

    =x(x-2)/(x²-1) *(x+1)/ x(x-2)

    =1/(x-1)

    =1/(2-1)

    =1