Question

问一道关于质量守恒定律的化学计算题

Answer 1

设生成CO2 x 克,CO y 克：

CH3CH2OH + 3O2 = 2CO2 + 3H2O

46.88.54

(46/88)x.x.(54/88)x

CH3CH2OH + 2O2 = 2CO + 3H2O

46.56.54

(46/56)y.y.(54/56)y

x + y = 27.6-10.8=16.8

(54/88)x + (54/56)y = 10.8

CO2:x=15.4g,CO:y=1.4g.

乙醇:(46/88)x + (46/56)y = 9.2g