先求周期:1)y=sin²x=(1-cos2x)/2,T=π2)y=|sinx|,y(x+π)=y(x),T=π3)y=(1-cos2x)/sin2x=2sin²x/(2sinxcosx)=sinx/cosx=tanx,T=π4)y=sin|x|,当x>0时,周期为2π.所以y的周期不是π再求增减性:因为sinx在...
有四个函数:①y=sin²x; ②y=|sinx|; ③y=(1-cos2x)/sin2x;④y=sin|x|
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