设a1x+b1y+c1z+d1=0为圈1(划一个圈放一个1)
a2x+b2y+c2z+d2=0为圈2
圈1乘c2-圈2乘以c1=
(a1c2-a2c1)x+(b1c2-b2c1)y+d1c2-d2c1=0
(b1c2-b2c1)y=d2c1-d1c2-(a1c2-a2c1)x
y=(d2c1-d1c2)/(b1c2-b2c1)--(a1c2-a2c1)/(b1c2-b2c1)x
设a1x+b1y+c1z+d1=0为圈1(划一个圈放一个1)
a2x+b2y+c2z+d2=0为圈2
圈1乘c2-圈2乘以c1=
(a1c2-a2c1)x+(b1c2-b2c1)y+d1c2-d2c1=0
(b1c2-b2c1)y=d2c1-d1c2-(a1c2-a2c1)x
y=(d2c1-d1c2)/(b1c2-b2c1)--(a1c2-a2c1)/(b1c2-b2c1)x