Question

如何配置盐酸(0.2mol/L)溶液1000ml

Answer 1

额,36%~38%我就取37%吧?

n(HCl)=(1000/1000)*0.2=0.2mol

m(HCl)=0.2*(1+35.5)=7.3g

所以,m盐酸=7.3/37%≈19.73g

V盐酸=19.73g/(1.18g/ml)=16.72ml

V水=1000-16.72=983.28ml