如何简便计算以下行列式:

1个回答

  • 一.公式法

    a+b a 0 ...0 0

    b a+b a ...0 0

    0 b a+b ...0 0

    .........

    0 0 0 ...a+b a

    0 0 0 ...b a+b

    当a≠b时,Dn = [a^(n+1)-b^(n+1)]/(a-b)

    行列式 = 3^6-2^6 = 665.

    二.化对角行列式

    5 3 0 0 0

    2 5 3 0 0

    0 2 5 3 0

    0 0 2 5 3

    0 0 0 2 5

    r2-(2/5)r1

    5 3 0 0 0

    0 19/5 3 0 0

    0 2 5 3 0

    0 0 2 5 3

    0 0 0 2 5

    r3-(10/19)r2

    5 3 0 0 0

    0 19/5 3 0 0

    0 0 65/19 3 0

    0 0 2 5 3

    0 0 0 2 5

    r4-(38/65)r3

    5 3 0 0 0

    0 19/5 3 0 0

    0 0 65/19 3 0

    0 0 0 211/65 3

    0 0 0 2 5

    r5-(130/211)r4

    5 3 0 0 0

    0 19/5 3 0 0

    0 0 65/19 3 0

    0 0 0 211/65 3

    0 0 0 0 665/211

    = 5*19/5*65/19*211/65*665/211

    = 665.