9^a=16^b=12
a=log9(12)
b=log16(12)
c=1/a+1/b=1/log9(12)+1/log16(12)=log12(9)+log12(16)=log12(9*16)=log12(12^2)=2
f(x)=t/(c^(-3x)+1)=t/(2^(-3x)+1)
9^a=16^b=12
a=log9(12)
b=log16(12)
c=1/a+1/b=1/log9(12)+1/log16(12)=log12(9)+log12(16)=log12(9*16)=log12(12^2)=2
f(x)=t/(c^(-3x)+1)=t/(2^(-3x)+1)