Question

勾股定理练习题已知三角形ABC中,三条边分别为a=n^2-1,b=2n,c=n^2+1(n>1).试判断该三角形是否是直

Answer 1

c^2-a^2=(c+a)(c-a)=(n^2+1+n^2-1)(n^2+1-n^2+1)

=2n^2*2

=4n^2

=(2n)^2

=b^2

所以a^2+b^2=c^2

所以是直角三角形

c所对的角是直角