Question

(1又1/1992*3.6+3又3/5*8又1991/1992)除9又3/5除3又3/4

Answer 1

(1又1/1992*3.6+3又3/5*8又1991/1992)除9又3/5除3又3/4

={(1993/1992)*3.6+(18/5)*(9*1992-1)/1992}/[(48/5)*(4/15)]

=[1993*3.6/1992+18*(9*1992-1)/(5*1992)]/(64/25)

={[1993*18+18*(1992*9-1)]/(5*1992)}/(64/25)

=[18*(1993-1+1992*9)]/(5*1992)}/(64/25)

=(18*1992*10)/(5*1992)}/(64/25)

=36/(64/25)

=36*25/64=225/16