Question

函数f(x)=x[1/(2^x+b)+1/a],其中a,b∈R,定义域为{x|x≠0},且f(2)=5/3,求函数f(x

Answer 1

从定义域可以看出2^0+b=0,则b=-1

将f(2)=5/3代入计算得a=2

f(x)=x[1/(2^x-1)+1/2]