标准状况下,将250体积的HCl气体 溶于1体积水中,所得溶液的密度为1.18g/mL .求此溶液中HCl 的质量分数

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  • 设水体积为1L,则水质量 = 1000g

    350L HCl物质的量 = 350/22.4 = 15.625mol

    m(HCl) = 15.635*36.5 = 570.3g

    m(盐酸) = 1000+570.3 = 1570.3g

    V(盐酸) = 1570.3/1.18 = 1331ml = 1.33L

    所以HCl质量分数 = 570.3/1570.3 = 36.3%

    物质的量浓度 = 15.625/1.33 = 11.75mol/L