标况下67.2升气体即为3mol,22.4L即为1mol.
设NO2为xmol,NH3为ymol,N2为zmol
3NO2+H2O=2HNO3+NO Δm
3mol 1mol 46*3-30=108g
x mol x/3 mol 108x/3 g
x+y+z=3
x/3+ z=1
108x/3 + 17y=71
解之即得
标况下67.2升气体即为3mol,22.4L即为1mol.
设NO2为xmol,NH3为ymol,N2为zmol
3NO2+H2O=2HNO3+NO Δm
3mol 1mol 46*3-30=108g
x mol x/3 mol 108x/3 g
x+y+z=3
x/3+ z=1
108x/3 + 17y=71
解之即得