△t1=(30.1-26.1)℃=4℃
△t2=(33.3-27.2)℃=6.1℃
△t3=(29.8-25.9)℃=3.9℃
△t4=(30.4-26.3)℃=4.1℃
因为△t2误差较大,舍去
所以△t=(4+3.9+4.1)℃/3=4℃
n(NaOH)=0.05L*0.50 mol/L=0.025mol
n(H2SO4)=2*0.03L*0.50 mol/L=0.03mol
生成n(H2O)=0.025mol
m=50 mL *1 g/cm3+30ml*1 g/cm3=80g
Q=mC△t=80g*4.18J/(g·℃)*4℃=1337.6J=1.3376KJ
△H=-1.337.6KJ/0.025mol=-53.5KJ/mol