80g硫酸铜饱和溶液,有水80*100/125=64g
设析出胆矾x克,
CuSO4 CuSO4·5H2O 5H2O
160 250 90
160x/250 x 90x/250
剩余水为(64-90x/250)g
剩余硫酸铜为80-64-160x/250 +5 = (21-160x/250)g
根据溶解度的计算,(21-160x/250)/(64-90x/250)=25/100
x=100/11=9.09
80g硫酸铜饱和溶液,有水80*100/125=64g
设析出胆矾x克,
CuSO4 CuSO4·5H2O 5H2O
160 250 90
160x/250 x 90x/250
剩余水为(64-90x/250)g
剩余硫酸铜为80-64-160x/250 +5 = (21-160x/250)g
根据溶解度的计算,(21-160x/250)/(64-90x/250)=25/100
x=100/11=9.09