答:
f(x)=5sinxcosx-(5√3/2)cos2x
=5*[(1/2)sin2x-(√3/2)cos2x]
=5*sin(2x-π/3)
1)
f(x)的最小正周期T=2π/2=π
2)
函数的最大值为5,最小值为-5