Question

1.ph=8的naoh和ph=12的Baoh2 等体积混合后Ph?

Answer 1

[OH-]=[(10^-6)+(10^-2)]/2=0.005

pOH=-lg[OH-]=2.30,pH=14-pOH=11.70

发生中和反应,假设体积分别都为1L,

[H+]=[0.1-0.01*2]/2=0.04

pH=-lg[H+]=1.40