Question

[(ab-bc)^2-(ab+bc)^2+2(ab+bc)(ab-bc)]/2b^2 化简

Answer 1

[(ab-bc)^2-(ab+bc)^2+2(ab+bc)(ab-bc)]/2b^2

=[(ab-bc)²-(ab+bc)²+2(ab+bc)(ab-bc)]/2b²

=[(ab-bc)²+(ab+bc)²-2(ab+bc)²+2(ab+bc)(ab-bc)]/2b²

=[【(ab-bc)+(ab+bc)】²-2(ab+bc)²]/2b²

=[【2ab】²-2b²(a+c)²]/2b²

=a²-(a+c)²

=a²-a²-2ac-c²

=-c(2a+c)