Question

e^xln(xy+1)的导数怎么求

Answer 1

令z=e^xln(xy+1)

zx=e^xln(xy+1)+e^x·1/(xy+1)·y

=e^xln(xy+1)+ye^x/(xy+1)

zy=e^x·1/(xy+1)·x=xe^x/(xy+1)