Question

y=∫(sint)^3dt,下限0,上限根号x,求dy/dx

Answer 1

∵y=∫(sint)^3dt

∴dy/dx=d(∫(sint)^3dt)/dx

=(sin(√x))^3*d(√x)/dx

=(sin(√x))^3*(1/(2√x))

=(sin(√x))^3/(2√x).