√2x-√3y=√6 ,(1)
√3x+√2y=2√6 (2)
(1)*√3= ==> √6x-3y=√18 ==> √6x=√18 +3y
(2)*√2= ==> √6x +2y =2√12 ====>√6x =2√12 -2y
√18+3y=2√12-2y
3y+2y=2*2√3-3√2
5y=4√3-3√2
y=(4√3-3√2)/5
√2x-√3y=√6 ===>x=(√6+√3y)/√2,
x=(√6+(12-3√6)/5)/√2
x=(5√6+12-3√6)*√2/2
x=(12√2+2√6*√2)/2
x=6√2+2√3
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