∫dx / √(9x² - 6x + 7)= ∫dx / √[(3x - 1)² + 6]= 1/3 *∫d(3x - 1) / √[(3x - 1)² + 6]根据:∫dt / √[t² + 6] = t √[t² + 6] / 2 + Ln[t + √[t² + 6]] / 2= 1/ 6 { (3x - ...
∫dx / √(9x² - 6x + 7)= ∫dx / √[(3x - 1)² + 6]= 1/3 *∫d(3x - 1) / √[(3x - 1)² + 6]根据:∫dt / √[t² + 6] = t √[t² + 6] / 2 + Ln[t + √[t² + 6]] / 2= 1/ 6 { (3x - ...