Question

20112数学初三丰台二模12题解析

Answer 1

ƒ(n)=1+2/n

ƒ(1)ƒ(2)ƒ(3).ƒ(100)=(1+2/1)(1+2/2)(1+2/3).(1+2/98)(1+2/99)(1+2/100)

=(3/1)(4/2)(5/3).(100/98)(101/99)(102/100)

=(1/1)(1/2).(101/1)(102/1)

=5151