Question

详细请看问题补充、、、该问题关于因式分解、

Answer 1

n(n+1)(n+2)(n+3)+1

=n(n+3)(n+1)(n+2)+1

=(n²+3n)(n²+3n+2)+1

令a=n²+3n

原式=a(a+2)+1

=a²+2a+1

=(a+1)²

=(n²+3n+1)²