Question

lg(x-√x^2-a^2)求导

Answer 1

(lgA)'=1/(A*ln10)

(x-√x^2-a^2)'=1- x/(√x^2-a^2)

所以由复合函数的求导法则可以知道

lg(x-√x^2-a^2)的导数=[1- x/(√x^2-a^2)] / [(x-√x^2-a^2)*ln10]