Question

用0.01mol/L的硫酸滴定0.01mol/L的氢氧化钠,中和后加水至100ml.①多加一滴硫酸②少加一滴硫酸.(一滴

Answer 1

V=100ml =0.1L

①多加一滴硫酸,一滴硫酸0.05ml:

n(H+)=2*0.01*0.05/1000 = 1*10^(-6) mol

[H+] =n(H+)/V =1*10^(-6)/0.1 =1*10^(-5) mol/L

②少加一滴硫酸:

n(OH-)=2*0.01*0.05/1000 =1*10^(-6) mol

[OH-]=n(OH-)/V =1*10^(-6)/0.1 =1*10^(-5) mol/L

[H+]=Kw/[OH-] =1*10^(-14)/10^(-5) =10^(-9) mol/L

①②中氢离子浓度之比=10^(-5)/10^(-9) =10000 :1