cos(π/4+X)=4/5,X∈(-π/2,-π/4),则π/4+X∈(-π/4,0),2X∈(-π,-π/2)sin(π/4+X)=-3/5,sin(π/2+2X)=2 sin(π/4+X)cos(π/4+X)=-24/25cos2X =sin(π/2+2X)=sin(π/2-2X)=-24/25,sin2X=-7/25(...
已知cos(π/4+x)=4/5,x∈(-π/2,-π/4).求(sin2x-2sin²x)/(1+tanx)
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