已知直线l1:x=my与抛物线C:y2=4x交于O (坐标原点),A两点,

1个回答

  • (1),联立x=my,y^2=4x,得:O、A的坐标分别为(0,0),(4m^2,4m);

    所以|OA|^2=16m^4+16m^2.

    联立x=my+m,y^2=4x,得:B、D的坐标分别为(x1,y1),(x2,y2);

    将x=my+m,代入y^2=4x,消去x,得:y^2-4my-4m=0,

    所以y1+y2=4m,y1y2=-4m,

    (y1-y2)^2=(y1+y2)^2-4y1y2=16m^2+16m;

    因为x1=my1+m,x2=my2+m,所以

    x1+x2=m(y1+y2)+2m=4m^2+2m,x1-x2=m(y1-y2),

    所以|BD|^2=(x1-X2)^2+(y1-y2)^2=(m^2+1)(x1-x2)^2

    =16(m^2+m)(m^2+1).

    又因为 | BD | = 2 | OA |,所以

    16(m^2+m)(m^2+1)=4(16m^4+16m^2),

    整理得:m(3m-1)(m^2+1)=0,

    因为 m^2+1>0,

    所以 m=0(舍去),m=1/3.

    故实数m的值为1/3.

    (2),三角形OAA1的面积S1

    =1/2*|AA1|*|yA|=1/2*|xA|*|yA|

    =1/2*|4m^2|*|4m|=8m^2*|m|;

    直线L2与y轴的交点C坐标为(0,-1).

    四边形BB1D1D的面积S2

    =|三角形CBB1的面积-三角形CDD1的面积|

    =|1/2*|BB1|*CB1-1/2*|DD1|*|CD1||

    =|1/2*|x1|*|y1+1|-1/2*|x2|*|y2+1||

    =|1/2*|x1|*|x1/m|-1/2*|x2|*|x2/m||

    =|x1^2-x2^2|/2|m|

    =|(x1+x2)(x1-x2)|/2|m|

    =|2m(2m+1)*4m根号(m^2+m)|/2|m|

    =4|2m^2+m|*根号(m^2+m).

    所以S1:S2=8m^2*|m|:4|2m^2+m|*根号(m^2+m)

    =2m^2:|2m+1|*根号(m^2+m).