Question

已知函数f(x)=x三次方-x²-4,求f(-1.2),f(3.7)的值

Answer 1

原式=x^2(x-1)-4

所以f(-1.2)=(-1.2)^2(-1.2-1)-4=1.44*(-2.2)-4=-3.168-4=-7.168.

f(3.7) =(3.7)^2(3.7-1)-4=13.69*2.7-4=36.963-4=32.963.