几道关于数学的二次根式的乘除!6道题都是计算!

2个回答

  • 1

    (a^2-b^2)/[-2(√bx)^5] *x^2/√(3a+3b) / (a-b)/(4√b/5)

    =√(a+b)/b^2 * [-2/(5√3)]

    2

    1/[(7y√y)/2x]^2 -x/y^3

    =4x^2/y^2-x/y^3

    3

    4

    3√(3 1/2)* (√1 4/7)/(-8) / √(51/2)/4

    =3(√7/√2)* (√11/√7)/(-8) *4√2/√11

    =-3/2

    5

    2(√(xy^5)/y * 3√(x^3y)/(-2) / √(y/x)/3)

    =-9x^2y√x√y

    6

    √(b/a) * (-5)(√a^3/b^3) *√(b^3/a^3)

    =-5√(b/a)