即xy=-2
x+y=3
原式=3xy+10y+5x-2xy-2y+3x
=xy+8x+8y
=xy+8(x+y)
=-2+8×3
=22
xy+ 2=0,x+y-3=0求(3xy+10y))+[5x-(2xy+2y-3x)]
3个回答
相关问题
-
x-y+3xy=0 求2x+3xy-2y/x-2xy-y的值
-
若（3xy+2）2+|7-x-y|=0，求代数式（5xy+10y）-[-5x-（4xy-2y+3x）]的值．
-
已知:x>0,y>0,且x- 10√xy+25y=0,求2x+√xy+3y/x+√xy-y
-
XY=1,X+Y=3,则3XY+10Y+[5X-(2XY+2Y-3X)]
-
若xy=-2,x+y=3,求代数式（3xy+10y)+{5x-(2xy+2y-3x)}的值
-
化简求值(0.2x^3-x^2y-xy^2)-(xy^2-x^2y-0.5x^3)+0.3x^3其中x=-3y=-2
-
已知y-x-2xy=0,求3x+xy-3y/y-xy-x的值
-
x/y=2,求x²-3xy+y²/2x²-3xy+5y²
-
5x²y-[2²y-(3xy-xy²)-3x²]-2xy²-y
-
x^2+y^2=3xy xy≠0 求x^2 y^-2 + x^-2 y^2