Question

●根据溶液稀释前后PH判断酸性强弱

Answer 1

PH=2则 才c(H+)=0.01mol/L

若稀释1000倍,若为强酸则才c(H+)=0.01/1000 =0.00001mol/L此时PH=5

若为弱酸,稀释过程也是促进电离过程,还会电离出H+,会使得c(H+)>0.00001mol/L,从而PH