解不等式(x2-3x+2)/(x2-5x-6)>(x2-5x-6)/(x2-3x+2)

3个回答

  • (x2-3x+2)/(x2-5x-6)>(x2-5x-6)/(x2-3x+2)

    (x-1)(x-2)/(x-6)(x+1)>(x-6)(x+1)/(x-1)(x-2)

    (x-1)(x-2)/(x-6)(x+1)-(x-6)(x+1)/(x-1)(x-2)>0

    [(x-1)(x-2)]^2-[(x-6)(x+1)]^2/ (x-6)(x+1)(x-1)(x-2)>0

    [(2x+8)(2x^2-8x-4)] / (x-6)(x+1)(x-1)(x-2)>0且x不等于6,-1,2,1

    (x+4)(x^2-4x-2) / (x-6)(x+1)(x-1)(x-2)>0且x不等于6,-1,2,1

    即(x+4)(x^2-4x-2) (x-6)(x+1)(x-1)(x-2)>0,(x^2-4x-2)=0得出x1=2+√6,x2=2-√6

    (x+4)(x^2-4x-2) (x-6)(x+1)(x-1)(x-2)>0利用穿线法得出

    X属于(-4,-1)或(2-√6,1)或(2,2+√6)