Question

求关于电解质溶液的计算问题题目是这样子的：用PH值为0.70的HCL溶液和PH为13.6的NaOH溶液制备100mLPH

Answer 1

设HCl的体积为XL,NaOH为0.1-XL

PH值为0.7的HCl,PH=-lg[H+],[H+]=0.2M,PH为13.6的NaOH,POH=-lg[OH-]=14-13.6=0.40; [OH-]=0.40M; PH为12; [OH-]=0.01M

中和反应是等MOL,碱过量,溶液显碱性.

0.40(0.1-X)/0.1-0.20X/0.1=0.01 ; X=0.065L=6.5ML;

答:需要盐酸为6.5毫升,NaOH为100-6.5=93.5ML