y=tan[(1+x/(a+b)]的周期T=π/[|1/(a+b)|]
y=sin((a-b)x+π/4)的周期T=2π/(|a-b|)
由题意,得
π/[1/(a+b)]=π
2π/(a-b)=3π
∴a+b=1
a-b=2/3
∴a=5/6
b=1/6
刚明白为什么是四种结果
第二种情况是:
π/[-1/(a+b)]=π
2π/[-(a-b)]=3π
此时,a+b=-1,b-a=2/3,
此时,a=-5/6,b=-1/6
第三种情况是:
π/[1/(a+b)]=π
2π/[-(a-b)]=3π
此时,a+b=1,b-a=2/3
∴a=1/6,b=5/6
第四种情况:
π/[-1/(a+b)]=π
2π/[(a-b)]=3π
此时a+b=-1,a-b=2/3
∴a=-1/6,b=-5/6
谢谢