Question

数学函数化简的问题!~~~~（x-3)/（x+3)（x-1) 怎么化简并求出值域?是要用到不等式来做

Answer 1

(X-3)/(X+3)(X-1)

=(X-3)/[(X-3)^2+8(X-3)+12]

=1/[(X-3)+8+1/(X-3)]

当X>3时

当