答案错了,应该是[Na+]>[CH3COO-]>[OH-]>[H+]
不过你的思考方式好像还是有点问题.
应该是NaOH+CH3COOH=CH3COONa+H2O
因为是等摩尔,所以最后恰好完全中和生成CH3COONa
然后CH3COONa=CH3COO- +Na+
CH3COO- +H2O=可逆=CH3COOH +OH-
因为水解,所以[Na+]>[CH3COO-] [OH-]>[H+]
而因为电离完全,水解很微弱,所以[CH3COO-]>[OH-]
所以[Na+]>[CH3COO-]>[OH-]>[H+]