(cos15°sin9°+sin6°)/(sin15°sin9°-cos6°)=

1个回答

  • 原式=[cos15°sin9°+sin(15°-9)]/[sin15°sin9-cos(15°-9°)]

    =(cos15°sin9+sin15°cos9°-cos15°sin9°)/(sin15°sin9°-cos15°cos9°-sin15°sin9°)

    =sin15°cos9°/(-cos15°cos9°)

    =sin15°/cos15°

    =-tan15°

    =-tan(45°-30°)

    =-(tan45°-tan30°)/(1+tan45°tan30°)

    =-2+√3

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