(x+y)(x+y+2xy)+(xy-1)(xy+1)
=(x+y)²+2xy(x+y)+(xy)²-1
=(x+y+xy)²-1
=(x+y+xy-1)(x+y+xy+1)
=(x+y+xy-1)(x+1)(y+1)
(x²-2x)(x²-2x-2)-3
=(x²-2x)²-2(x²-2x)-3
=[(x²-2x)-3][(x²-2x)+1]
(x-3)(x+1)(x-1)²
(x+y)(x+y+2xy)+(xy-1)(xy+1)
=(x+y)²+2xy(x+y)+(xy)²-1
=(x+y+xy)²-1
=(x+y+xy-1)(x+y+xy+1)
=(x+y+xy-1)(x+1)(y+1)
(x²-2x)(x²-2x-2)-3
=(x²-2x)²-2(x²-2x)-3
=[(x²-2x)-3][(x²-2x)+1]
(x-3)(x+1)(x-1)²