数项有n+1
偶数项是n
则奇数和=[a1+a(2n+1)](n+1)/2=290
偶数和=[a2+a(2n)]n/2=261
等差则a1+a(2n+1)=a2+a2n
所以相除有(n+1)/n=290/261=10/9
n=9
2n+1=19
甲数是百分之四十,比乙数大百分之三十,甲数是乙数的百分之( ),乙数是甲数的百分之( ).
数项有n+1
偶数项是n
则奇数和=[a1+a(2n+1)](n+1)/2=290
偶数和=[a2+a(2n)]n/2=261
等差则a1+a(2n+1)=a2+a2n
所以相除有(n+1)/n=290/261=10/9
n=9
2n+1=19