Question

设计一个三角形类要求：1、足够的可以描述三角形的数据、函数成员.2、用成员函数判断两个三角形是否相似.3、重载操作符“=

Answer 1

#include

using namespace std;

class Triangle

{

public:

Triangle(double a,double b,double c);

bool similar(Triangle &t);

bool operator = (Triangle &t);

void set(double a,double b,double c);

// void get(double &a,double &b,double &c);

private:

double a,b,c;

double ja,jb,jc;

};

Triangle::Triangle(double a,double b,double c)

{

this->a=a;

this->b=b;

this->c=c;

this->ja=arccos ((b^2+c^2-a^2)/(2*b*c));

this->jb=arcos((a^2+c^2-b^2)/(2*a*c));

this->jc=arcos((a^2+b^2-c^2)/(2*a*b));

}

bool Triangle::similar(Triangle &t)

{

double x[3]={t.ja,t.jb,t.jc};

double y[3]={this->ja,this->jb,this->jc};

int i,j;

double temp;

for(i=0; iy[j])

{

temp=y[i];

y[i]=y[j];

y[j]=temp;

}

}

}

if((x[0]/y[0]-x[1]/y[1]b,this->c};

int i,j;

double temp;

for(i=0; iy[j])

{

temp=y[i];

y[i]=y[j];

y[j]=temp;

}

}

}

if((x[0]-y[0]c=c;

this->ja=arccos ((b^2+c^2-a^2)/(2*b*c));

this->jb=arcos((a^2+c^2-b^2)/(2*a*c));

this->jc=arcos((a^2+b^2-c^2)/(2*a*b));

}

void Triangle::get(double &a,double &b,double &c)

{

a=this->a;

b=this->b;

c=this->c;

}

int main()

{

Triangle t1(1,2,2),t2(1,1,1.414);

if(t1.similar(t2))

{

cout