Question

约分：-36x的2n-1次方y的n次方分之12x的2n+1次方y的n-2次方

Answer 1

[12x^(2n+1)y^(n-2)]/[-36x^(2n-1)*y^n]

=[12x^(2n-1)*x^2*y^(n-2))]/[-36x^(2n-1)*y^(n-2)*y^2]

=-x²/3y²