氧化剂K2Cr2O7 还原剂CH3CH2OH
氧化产物CH3COOH 还原产物Cr2(SO4)3
前一个C是-4价 后一个C是+4价
高一化学问题2K2Cr2O7+3CH3CH2OH+8H2SO4=2K2SO4+2Cr2(SO4)3+3CH3COOH+1
3个回答
相关问题
-
K2Cr2O7+CH3CH2OH+H2SO4－－Cr2(SO4)3+CH3COOH+K2SO4+H2O
-
2K2Cr2O7+3CH3CH2OH+8H2SO4－－2Cr2(SO4)3+ 3CH3COOH+2K2SO4+11H2O
-
2K2Cr2O7+3CH3CH2OH+8H2SO4=2Cr2(SO4)3+3CH3COOH+2K2SO4+11H2O 的
-
K2CrO7+CH3CH2OH+H2SO4==Cr2(SO4)3+CH3COOH+K2SO4+H2O
-
K2Cr2O7与乙醇的反应.K2Cr2O7与乙醇 2K2Cr2O7+3CH3CH2OH+8H2SO4－－2Cr2(SO4
-
2K2Cr2O7+3C2H5OH+8H2SO4=2K2SO4+2Cr(SO4)3+3CH3COOH+11H2O是否为还原
-
配平：K2Cr2O7+C2H5OH+H2SO4=Cr2(SO4)3+CH3COOH+K2SO4+_____(此物质未知)
-
a K2Cr2O7(橙红色）+ b C2H5OH+ c H2SO4 ====d CR2(SO4)3(绿色）+ e CH3
-
K2Cr2O7+H2SO4+K2SO3=K2SO4+Cr2(SO4)3+H2O
-
H2SO4+CH3OH+K2Cr2O4反应的方程式怎么写