Question

已知2x+4y-3=0,求（2的x次方×4的y次方）的4次方的值

Answer 1

2x+4y-3=0

2x+4y=3

(2^x×4^y)^4

=(2^2x×4^2y)^2

=(2^2x×2^4y)^2

=[2^(2x+4y)]^2

=(2^3)^2

=8^2=64