Question

y=ax的平方+bx+c与y=a(x-b)平方+k配方的过程

Answer 1

y=a(x²+bx/a)+c

=a[x²+bx/a+b²/(4a²)-b²/(4a²)]+c

=a[x²+bx/a+b²/(4a²)]-ab²/(4a²)]+c

=a[x+b/(2a)]²-b²/(4a)+c

=a{x-[-b/(2a)]}²+(4ac-b²)/(4a)