Question

(x^2-9分之x+3+6+x-x^2分之x)乘以4x-6分之3-x

Answer 1

(x^2-9分之x+3+6+x-x^2分之x)乘以4x-6分之3-x

=[（x+3）/(x²-9）+x/(6+x-x^2)]×（3-x）/(4x-6)

=[1/(x-3)+x/(x+2)(3-x)]×（3-x）/(4x-6)

=(-1+x/(x-2)]×1/(4x-6)

=(-x+2+x)/(x-2)(4x-6)

=2/(x-2)(4x-6)

=1/(x-2)(2x-3)